PROVE THAT PARALLELOGRAM CIRCUMSERIBING A CIRCLE IS RHOMBUS

Actually it wil be not rhombus but it will be rectangle..

let me prove it

since we know that in parallelogram  opposite angles are equal..

and in cyclic quadrilateral the sum of the opposite angles is 180 degree

so let one angle of the parallelo gram be x then the opposite angle will also be x

so 2x = 180

so x =90

so the angles will be 90 degree...so the given parallelo gram will be rectangle but not rhombus