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Eliminate thita between the equation
x=asecthita, y=btanthita
Posted by: raju shrestha in Trigonometry 3 months ago, Total Answer(s): 1
Answer(s)
x=asecthita, y=btanthita
x/a = secthita, and y/b=tanthita
x^2/a^2 = sec^2 thita, y^2/b^2 = tan^2 thita
We know that,
Sec^2 thita - Tan^2 thita = 1
Therefore, we get
(x^2/a^2) - (y^2/b^2) = 1
By: vidyasagar, 3 months ago
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